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Algebraic Topology

  1. add Prove that the groups (2Z,+) and (Z,+) are isomorphic.

    Define the function ϕ:Z2Z by ϕ(n)=2n for all nZ. We will first show that ϕ is a bijection.

    Assume that ϕ(a)=ϕ(b). Then 2a=2b which implies a=b. Hence, ϕ is injective. Now, let n2Z. Since n is even, n=2k for kZ. Now, ϕ(k)=2k=n and ϕ is surjective. Since ϕ is both injective and surjective, it is bijective.

    Lastly, we have ϕ(a+b)=2(a+b)=2a+2b=ϕ(a)+ϕ(b)

    Thus, (2Z,+) and (Z,+) are isomorphic.

    Q.E.D.